16x^2+160x+384=0

Solution for 16x^2+160x+384=0 equation:

16x^2+160x+384=0

a = 16; b = 160; c = +384;
Δ = b2-4ac
Δ = 1602-4·16·384
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-32}{2*16}=\frac{-192}{32}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+32}{2*16}=\frac{-128}{32}
=-4
$